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Solving problem N3896 Bayesian probability theory
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Uploaded: 08.02.2019
Content: teorver_3896.doc 28,5 kB
Product description
3896. Three workers handle the same type of parts. The first one processed 20 parts for a shift, the second - 25, the third - 15. The probability of marriage for the first worker is 0.03, for the second - 0.02, for the third - 0.04. From the total output for a change at random, one detail was taken and tested, which turned out to be defective. Find the probability that it is processed by the second worker.
Additional information
Detailed solution. Decorated in Microsoft Word 2003 (Quest decided to use the formula editor)
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