8. Iron conductor (ρ = 7,87 g / cm 3, M = 56 · 10-

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8. Iron conductor (ρ = 7,87 g / cm 3, M = 56 · 10-3 kg / mol) of section S = 0,5 mm2 current flows I = 0,1 A. Determine the average velocity of ordered (directed) motion electrons, assuming that the number of free electrons n per unit volume of the conductor is equal to the number of atoms n ´in the unit volume of the conductor.

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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)

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