93. A flat coil of turns N = 500 R = radius of 10 cm is

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93. A flat coil of turns N = 500 R = radius of 10 cm is in the magnetic field intensity H = 20 kA / m. The plane perpendicular to the direction of the coil field. Current flows through the coil I = 5 A. What has to be performed in order to rotate the coil by the angle φ = 90 ° around an axis coinciding with the diameter of the coil.

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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)


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