Solution of task 123 of Chemistry Book Shimanovich 2003

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123. The reaction proceeds according to the equation N2 + O2 = 2NO.
The concentrations of the starting materials before the start of the reaction were: [N2] = 0.049 mol / l; [O2] = 0.01 mol / l.
Calculate the concentration of these substances at the time when [NO] = 0.005 mol / l.

The answer is: [N2] = 0.0465 mol / l; [O2] = 0.0075 mol / l.

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